A 5-circle incidence theorem: Difference between revisions

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Line 24: Line 24:
var attB = {name:'',strokeColor:'#EA0000',fillColor:'#EA0000'};
var attB = {name:'',strokeColor:'#EA0000',fillColor:'#EA0000'};
for (k = 0; k < 5; k++) {
for (k = 0; k < 5; k++) {
   B[k] = brd.create('intersection', [s[k], s[(k-1)%5], attB);
   B[k] = brd.create('intersection', [s[k], s[(k-1)%5, 0], attB);
}
}




</jsxgraph>
</jsxgraph>

Revision as of 12:09, 13 August 2019