# Difference between revisions of "Vertex equations of a quadratic function and it's inverse"

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''y = a (x-v_x)^2 + v_y''. | ''y = a (x-v_x)^2 + v_y''. | ||

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+ | ''a'' can be determined by solving | ||

+ | |||

+ | ''p_y = a (p_x-v_x)^2 + v_y'' for ''a''. | ||

## Revision as of 11:31, 16 December 2014

A parabola can be uniquely defined by its vertex *V* and one more point *P*.
The function term of the parabola then has the form

*y = a (x-v_x)^2 + v_y*.

*a* can be determined by solving

*p_y = a (p_x-v_x)^2 + v_y* for *a*.

### JavaScript code

```
var b = JXG.JSXGraph.initBoard('box1', {boundingbox: [-5, 5, 5, -5], grid:true});
var v = b.create('point', [0,0], {name:'V'}),
p = b.create('point', [3,3], {name:'P'}),
f = b.create('functiongraph', [
function(x) {
var den = p.X()- v.X(),
a = (p.Y() - v.Y()) / (den * den);
return a * (x - v.X()) * (x - v.X()) + v.Y();
}]);
})();
```

### JavaScript code

```
var b = JXG.JSXGraph.initBoard('box2', {boundingbox: [-5, 5, 5, -5], grid:true});
var v = b.create('point', [0,0], {name:'V'}),
p = b.create('point', [3,3], {name:'P'}),
f = b.create('functiongraph', [
function(x) {
var den = p.Y()- v.Y(),
a = (p.X() - v.X()) / (den * den);
return Math.sqrt((x - v.X()) / a) + v.Y();
}]);
```