Vertex equations of a quadratic function and it's inverse: Difference between revisions
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Conversely, also the inverse quadratic function can be uniquely defined by its vertex ''V'' and one more point ''P''. | |||
The function term of the inverse function has the form | |||
''y = sqrt((x-v_x)/a) + v_y''. | |||
''a'' can be determined by solving | |||
''p_y = sqrt((p_x-v_x)/a) + v_y'' for ''a'' which gives | |||
'' a = (p_x - v_x) / (p_y - v_y)^2 ''. | |||
<jsxgraph width="300" height="300" box="box2"> | <jsxgraph width="300" height="300" box="box2"> |
Revision as of 10:35, 16 December 2014
A parabola can be uniquely defined by its vertex V and one more point P. The function term of the parabola then has the form
y = a (x-v_x)^2 + v_y.
a can be determined by solving
p_y = a (p_x-v_x)^2 + v_y for a which gives
a = (p_y - v_y) / (p_x - v_x)^2 .
JavaScript code
var b = JXG.JSXGraph.initBoard('box1', {boundingbox: [-5, 5, 5, -5], grid:true});
var v = b.create('point', [0,0], {name:'V'}),
p = b.create('point', [3,3], {name:'P'}),
f = b.create('functiongraph', [
function(x) {
var den = p.X()- v.X(),
a = (p.Y() - v.Y()) / (den * den);
return a * (x - v.X()) * (x - v.X()) + v.Y();
}]);
})();
Conversely, also the inverse quadratic function can be uniquely defined by its vertex V and one more point P. The function term of the inverse function has the form
y = sqrt((x-v_x)/a) + v_y.
a can be determined by solving
p_y = sqrt((p_x-v_x)/a) + v_y for a which gives
a = (p_x - v_x) / (p_y - v_y)^2 .
JavaScript code
var b = JXG.JSXGraph.initBoard('box2', {boundingbox: [-5, 5, 5, -5], grid:true});
var v = b.create('point', [0,0], {name:'V'}),
p = b.create('point', [3,3], {name:'P'}),
f = b.create('functiongraph', [
function(x) {
var den = p.Y()- v.Y(),
a = (p.X() - v.X()) / (den * den);
return Math.sqrt((x - v.X()) / a) + v.Y();
}]);