# Difference between revisions of "Polynomial curve of constant width"

The curve defined by

$p(\phi) = a\cdot cos(k\cdot\phi/2)+b$

in polar form is smooth and of constant width for odd values of $k$. In the visuzalitaion with JSXGraph below $k$ is determined

$k = 2k'+1.$

### The underlying JavaScript code

var brd = JXG.JSXGraph.initBoard('jxgbox',{boundingbox:[-8,8,8,-8], keepaspectratio:true});
brd.suspendUpdate();
var a = brd.create('slider',[[-1,1.8],[1,1.8],[-5,0.20,5]], {name:'a'});
var b = brd.create('slider',[[-1,1.6],[1,1.6],[-5,1.15,10]], {name:'b'});
var k = brd.create('slider',[[-1,1.4],[1,1.4],[1,1,11]], {name:'k\'', snapWidth:1});

var c = brd.create('curve',[function(phi, suspendUpdate){
var kk, aa, bb, p, ps, co, si;
//if (!suspendUpdate) {
aa = a.Value();
bb = b.Value();
kk = 2*k.Value()+1;
//}
co = Math.cos(kk*phi*0.5);
si = Math.sin(kk*phi*0.5);
p  =  aa*co*co+bb;
ps = -aa*kk*co*si;
return p*Math.cos(phi)-ps*Math.sin(phi);
},
function(phi, suspendUpdate){
var kk, aa, bb, p, ps, co, si;
//if (!suspendUpdate) {
aa = a.Value();
bb = b.Value();
kk = 2*k.Value()+1;
//}
co = Math.cos(kk*phi*0.5);
si = Math.sin(kk*phi*0.5);
p  =  aa*co*co+bb;
ps = -aa*kk*co*si;
return p*Math.sin(phi)+ps*Math.cos(phi);
},