Difference between revisions of "Newton's root finding method"
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Jump to navigationJump to searchA WASSERMANN (talk | contribs) |
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<td> | <td> | ||
<form> | <form> | ||
| − | <input style="border:none; background-color:#efefef;padding:5px;margin-left:2px;" type="text" id="graphterm" value="x*x" size=" | + | <input style="border:none; background-color:#efefef;padding:5px;margin-left:2px;" type="text" id="graphterm" value="x*x" size="30"/> |
<input type="button" value="set function term" onClick="newGraph(document.getElementById('graphterm').value);"> | <input type="button" value="set function term" onClick="newGraph(document.getElementById('graphterm').value);"> | ||
</form> | </form> | ||
| Line 31: | Line 31: | ||
<jsxgraph width="600" height="500"> | <jsxgraph width="600" height="500"> | ||
var i; | var i; | ||
| − | var board = JXG.JSXGraph.initBoard('jxgbox', {boundingbox:[-5, | + | var board = JXG.JSXGraph.initBoard('jxgbox', {boundingbox:[-5,10,5,-2], axis:true}); |
var ax = board.create('axis', [[0,0], [1,0]], {strokeColor: 'black'}); | var ax = board.create('axis', [[0,0], [1,0]], {strokeColor: 'black'}); | ||
var ay = board.create('axis', [[0,0], [0,1]], {strokeColor: 'black'}); | var ay = board.create('axis', [[0,0], [0,1]], {strokeColor: 'black'}); | ||
Revision as of 16:15, 3 February 2010
xo is the start value. Drag it. You may change the function term here:
