Difference between revisions of "Newton's root finding method"
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Jump to navigationJump to searchA WASSERMANN (talk | contribs) |
A WASSERMANN (talk | contribs) |
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| Line 8: | Line 8: | ||
<td> | <td> | ||
<form> | <form> | ||
| − | <input style="border:none; background-color:#efefef;padding:5px;margin-left:2px;" type="text" id="graphterm" value="x*x*x/5" size="30"/> | + | <input style="border:none; background-color:#efefef;padding:5px;margin-left:2px;" type="text" id="graphterm" value="x*x*x/5" size="30"/><input type="button" value="set function term" onClick="newGraph(document.getElementById('graphterm').value);"> |
| − | <input type="button" value="set function term" onClick="newGraph(document.getElementById('graphterm').value);"> | ||
</form> | </form> | ||
</td> | </td> | ||
| Line 65: | Line 64: | ||
</jsxgraph> | </jsxgraph> | ||
You also may try the following function terms: | You also may try the following function terms: | ||
| − | Math.sin(x) | + | * <math>Math.sin(x)</math> |
| − | Math.exp(x) | + | * <math>Math.exp(x)</math> |
| − | Math.pow(2,x) | + | * <math>Math.pow(2,x)</math> |
| − | 1-2/(x*x) | + | * <math>1-2/(x*x)</math> |
| + | |||
| + | ===The underlying JavaScript code=== | ||
Revision as of 16:20, 3 February 2010
xo is the start value. Drag it. You may change the function term here:
You also may try the following function terms:
- [math]Math.sin(x)[/math]
- [math]Math.exp(x)[/math]
- [math]Math.pow(2,x)[/math]
- [math]1-2/(x*x)[/math]
