Difference between revisions of "Newton's root finding method"

From JSXGraph Wiki
Jump to: navigation, search
Line 8: Line 8:
 
<td>
 
<td>
 
<form>
 
<form>
<input style="border:none; background-color:#efefef;padding:5px;margin-left:2px;" type="text" id="graphterm" value="x*x" size="30"/>
+
<input style="border:none; background-color:#efefef;padding:5px;margin-left:2px;" type="text" id="graphterm" value="x*x*x/5" size="30"/>
 
<input type="button" value="set function term" onClick="newGraph(document.getElementById('graphterm').value);">
 
<input type="button" value="set function term" onClick="newGraph(document.getElementById('graphterm').value);">
 
</form>
 
</form>
Line 15: Line 15:
 
<script type="text/javascript">
 
<script type="text/javascript">
 
// Initial function term
 
// Initial function term
var term = function(x) { return x*x; };
+
var term = function(x) { return x*x*x/5; };
 
var graph = function(x) { return term(x); };
 
var graph = function(x) { return term(x); };
 
 
Line 63: Line 63:
 
         board.update();
 
         board.update();
 
}
 
}
 
 
 
</jsxgraph>
 
</jsxgraph>
 +
You also may try the following function terms:
 +
Math.sin(x)
 +
Math.exp(x)
 +
Math.pow(2,x)
 +
1-2/(x*x)

Revision as of 16:19, 3 February 2010

xo is the start value. Drag it.

You may change the function term here:
f(x) =
 
You also may try the following function terms: Math.sin(x) Math.exp(x) Math.pow(2,x) 1-2/(x*x)