Difference between revisions of "Newton's root finding method"

Revision as of 16:14, 3 February 2010

x_o is the start value. Drag it.

You may change the function term here:

f(x) =

@@ Line 14: / Line 14: @@
 <tr><td>&nbsp;</td></tr>
 <script type="text/javascript">
-function newGraph(v) {
-	eval("term = function(x){ return "+v+";}");
-	graph = function(x) { return term(x); };
-	g.Y = function(x){ return term(x); };
-	g.updateCurve();
-        board.update();
-}
 // Initial function term
 //var term = function(x) { return x*x; };
 //var graph = function(x) { return term(x); };
 var term, graph;
-newGraph(document.getElementById('graphterm').value);
 // Recursion depth
@@ Line 46: / Line 35: @@
 var ax = board.create('axis', [[0,0], [1,0]], {strokeColor: 'black'});
 var ay = board.create('axis', [[0,0], [0,1]], {strokeColor: 'black'});
+newGraph(document.getElementById('graphterm').value);
 var g = board.create('functiongraph', [function(x){return graph(x);}],{strokeWidth: 2, dash:0});
 var x = board.create('glider',[s,0,ax], {name: 'x_{0}', strokeColor: 'magenta', fillColor: 'yellow'});
@@ Line 66: / Line 59: @@
      }
 }
+function newGraph(v) {
+	eval("term = function(x){ return "+v+";}");
+	graph = function(x) { return term(x); };
+	g.Y = function(x){ return term(x); };
+	g.updateCurve();
+        board.update();
+}
 </jsxgraph>