Newton's root finding method: Difference between revisions

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Line 8: Line 8:
<td>
<td>
<form>
<form>
<input style="border:none; background-color:#efefef;padding:5px;margin-left:2px;" type="text" id="graphterm" value="x*x" size="30"/>
<input style="border:none; background-color:#efefef;padding:5px;margin-left:2px;" type="text" id="graphterm" value="x*x*x/5" size="30"/>
<input type="button" value="set function term" onClick="newGraph(document.getElementById('graphterm').value);">
<input type="button" value="set function term" onClick="newGraph(document.getElementById('graphterm').value);">
</form>
</form>
Line 15: Line 15:
<script type="text/javascript">
<script type="text/javascript">
// Initial function term
// Initial function term
var term = function(x) { return x*x; };
var term = function(x) { return x*x*x/5; };
var graph = function(x) { return term(x); };
var graph = function(x) { return term(x); };
Line 63: Line 63:
         board.update();
         board.update();
}
}
</jsxgraph>
</jsxgraph>
You also may try the following function terms:
Math.sin(x)
Math.exp(x)
Math.pow(2,x)
1-2/(x*x)

Revision as of 14:19, 3 February 2010

xo is the start value. Drag it.

You may change the function term here:
f(x) =
 

You also may try the following function terms: Math.sin(x) Math.exp(x) Math.pow(2,x) 1-2/(x*x)