Lagrange interpolation (dup)

From JSXGraph Wiki
Revision as of 19:18, 28 November 2008 by A WASSERMANN (talk | contribs) (New page: Construct a polynomial of degree 3 through four given points. <html> <link rel="stylesheet" type="text/css" href="http://jsxgraph.uni-bayreuth.de/distrib/jsxgraph.css" /> <script type="tex...)
(diff) ← Older revision | Latest revision (diff) | Newer revision → (diff)
Jump to navigationJump to search

Construct a polynomial of degree 3 through four given points.

        board = JXG.JSXGraph.initBoard('box', {originX: 250, originY: 250, unitX: 50, unitY: 25});
        // Axes
        b1axisx = board.createElement('axis', [[0,0], [1,0]], {});
        b1axisy = board.createElement('axis', [[0,0], [0,1]], {});

        var p = [];
        p[0] = board.createElement('point', [-1,2], {style:6});
        p[1] = board.createElement('point', [0,-3], {style:6});
        p[2] = board.createElement('point', [1,4], {style:6});
        p[3] = board.createElement('point', [2,1], {style:6});
        
        var polynomial = function(x) {
                var y = p[0].Y()*(x-p[1].X())*(x-p[2].X())*(x-p[3].X())/
                        ((p[0].X()-p[1].X())*(p[0].X()-p[2].X())*(p[0].X()-p[3].X()))+
                        p[1].Y()*(x-p[0].X())*(x-p[2].X())*(x-p[3].X())/
                        ((p[1].X()-p[0].X())*(p[1].X()-p[2].X())*(p[1].X()-p[3].X()))+
                        p[2].Y()*(x-p[0].X())*(x-p[1].X())*(x-p[3].X())/
                        ((p[2].X()-p[0].X())*(p[2].X()-p[1].X())*(p[2].X()-p[3].X()))+
                        p[3].Y()*(x-p[0].X())*(x-p[1].X())*(x-p[2].X())/
                        ((p[3].X()-p[0].X())*(p[3].X()-p[1].X())*(p[3].X()-p[2].X()));
                return y;
            };
        graph = board.createElement('curve', ['x', polynomial, 'x', -10, 10], {curveType:'graph'});