Difference between revisions of "A 5-circle incidence theorem"

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Line 20: Line 20:
 
   s[k] = brd.create('segment',[A[k], A[(k + 2) % 5]],{strokeColor:'blue',strokeWidth:1});
 
   s[k] = brd.create('segment',[A[k], A[(k + 2) % 5]],{strokeColor:'blue',strokeWidth:1});
 
}
 
}
 +
 +
 +
var attB = {name:'',strokeColor:'#EA0000',fillColor:'#EA0000'};
 +
for (k = 0; k < 5; k++) {
 +
  B[k] = brd.create('intersection', [s[k], s[(k-1)%5], attB);
 +
}
 +
  
 
</jsxgraph>
 
</jsxgraph>

Revision as of 13:09, 13 August 2019