Newton's root finding method

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Revision as of 14:19, 3 February 2010 by A WASSERMANN (talk | contribs)

xo is the start value. Drag it.

You may change the function term here:
f(x) =
 
x0 =
x1 =
x2 =
x3 =
x4 =
x5 =
x6 =
x7 =
x8 =
x9 =
x10 =

1234−1−2−3−4123456789−11234−1−2−3−4123456789−1
x0
You also may try the following function terms: Math.sin(x) Math.exp(x) Math.pow(2,x) 1-2/(x*x)

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