Newton's root finding method: Difference between revisions
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A WASSERMANN (talk | contribs) No edit summary |
A WASSERMANN (talk | contribs) No edit summary |
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<td> | <td> | ||
<form> | <form> | ||
<input style="border:none; background-color:#efefef;padding:5px;margin-left:2px;" type="text" id="graphterm" value="x*x*x/5" size="30"/> | <input style="border:none; background-color:#efefef;padding:5px;margin-left:2px;" type="text" id="graphterm" value="x*x*x/5" size="30"/><input type="button" value="set function term" onClick="newGraph(document.getElementById('graphterm').value);"> | ||
<input type="button" value="set function term" onClick="newGraph(document.getElementById('graphterm').value);"> | |||
</form> | </form> | ||
</td> | </td> | ||
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</jsxgraph> | </jsxgraph> | ||
You also may try the following function terms: | You also may try the following function terms: | ||
Math.sin(x) | * <math>Math.sin(x)</math> | ||
Math.exp(x) | * <math>Math.exp(x)</math> | ||
Math.pow(2,x) | * <math>Math.pow(2,x)</math> | ||
1-2/(x*x) | * <math>1-2/(x*x)</math> | ||
===The underlying JavaScript code=== | |||
Revision as of 14:20, 3 February 2010
xo is the start value. Drag it. You may change the function term here:
You also may try the following function terms:
- [math]\displaystyle{ Math.sin(x) }[/math]
- [math]\displaystyle{ Math.exp(x) }[/math]
- [math]\displaystyle{ Math.pow(2,x) }[/math]
- [math]\displaystyle{ 1-2/(x*x) }[/math]
