Polynomial curve of constant width: Difference between revisions
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                               var co = Math.cos(kk*phi*0.5);  |                                var co = Math.cos(kk*phi*0.5);  | ||
                               return aa*co*co+bb;  |                                return aa*co*co+bb;  | ||
                              },[0,0], 0,Math.PI*2], {curveType:'polar', strokeWidth:  |                               },[0,0], 0,Math.PI*2], {curveType:'polar', strokeWidth:10, strokeColor:'#ad5544'});  | ||
brd.unsuspendUpdate();  | brd.unsuspendUpdate();  | ||
</jsxgraph>  | </jsxgraph>  | ||
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                               var co = Math.cos(kk*phi*0.5);  |                                var co = Math.cos(kk*phi*0.5);  | ||
                               return aa*co*co+bb;  |                                return aa*co*co+bb;  | ||
                              },[0,0], 0,Math.PI*2], {curveType:'polar', strokeWidth:  |                               },[0,0], 0,Math.PI*2], {curveType:'polar', strokeWidth:10, strokeColor:'#ad5544'});  | ||
brd.unsuspendUpdate();  | brd.unsuspendUpdate();  | ||
</source>  | </source>  | ||
Revision as of 20:00, 6 October 2010
The curve defined by
- [math]\displaystyle{ p(\phi) = a\cdot cos(k\cdot\phi/2)+b }[/math]
 
in polar form is smooth and of constant width for odd values of [math]\displaystyle{ k }[/math].
References
The underlying JavaScript code
var brd = JXG.JSXGraph.initBoard('jxgbox',{boundingbox:[-2,2,2,-2], keepaspectratio:true});
brd.suspendUpdate();
var a = brd.create('slider',[[-1,1.8],[1,1.8],[-5,0.20,5]], {name:'a'});
var b = brd.create('slider',[[-1,1.6],[1,1.6],[-5,1.15,10]], {name:'b'});
var k = brd.create('slider',[[-1,1.4],[1,1.4],[1,1,11]], {name:'k\'', snapWidth:1});
var p = brd.create('curve',[function(phi, suspendUpdate){ 
                              var kk, aa, bb;
                              if (!suspendUpdate) {
                                aa = a.Value();
                                bb = b.Value();
                                kk = 2*k.Value()+1;
                              }
                              var co = Math.cos(kk*phi*0.5);
                              return aa*co*co+bb;
                             },[0,0], 0,Math.PI*2], {curveType:'polar', strokeWidth:10, strokeColor:'#ad5544'});
brd.unsuspendUpdate();