JSXGraph
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Rose
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<iframe 
    src="http://jsxgraph.uni-bayreuth.de/share/iframe/rose" 
    style="border: 1px solid black; overflow: hidden; width: 550px; aspect-ratio: 55 / 65;" 
    name="JSXGraph example: Rose" 
    allowfullscreen
></iframe>
This code has to 
<div id="board-0-wrapper" class="jxgbox-wrapper " style="width: 100%; ">
   <div id="board-0" class="jxgbox" style="aspect-ratio: 1 / 1; width: 100%;" data-ar="1 / 1"></div>
</div>

<script type = "text/javascript"> 
    /*
    This example is licensed under a 
    Creative Commons Attribution ShareAlike 4.0 International License.
    https://creativecommons.org/licenses/by-sa/4.0/
    
    Please note you have to mention 
    The Center of Mobile Learning with Digital Technology
    in the credits.
    */
    
    const BOARDID = 'board-0';

     var board2 = JXG.JSXGraph.initBoard(BOARDID, { axis: true, boundingbox: [-10, 10, 10, -10], keepaspectratio: true });
     var f = board2.create('slider', [[1, 8], [6, 8], [0, 4, 8]]);
     var len = board2.create('slider', [[1, 7], [6, 7], [0, 2, 8]], { snapWidth: 1, name: 'len' });
     var k = board2.create('slider', [[1, 6], [6, 6], [0, 2, 12]], { snapWidth: 0.2, name: 'k' });
     var c = board2.create('curve', [function(phi) { return f.Value() * Math.cos(k.Value() * phi); }, [0, 0], 0,
     function() { return len.Value() * Math.PI; }], { curveType: 'polar', strokewidth: 2 });
 </script> 
/*
This example is licensed under a 
Creative Commons Attribution ShareAlike 4.0 International License.
https://creativecommons.org/licenses/by-sa/4.0/

Please note you have to mention 
The Center of Mobile Learning with Digital Technology
in the credits.
*/

const BOARDID = 'your_div_id'; // Insert your id here!

 var board2 = JXG.JSXGraph.initBoard(BOARDID, { axis: true, boundingbox: [-10, 10, 10, -10], keepaspectratio: true });
 var f = board2.create('slider', [[1, 8], [6, 8], [0, 4, 8]]);
 var len = board2.create('slider', [[1, 7], [6, 7], [0, 2, 8]], { snapWidth: 1, name: 'len' });
 var k = board2.create('slider', [[1, 6], [6, 6], [0, 2, 12]], { snapWidth: 0.2, name: 'k' });
 var c = board2.create('curve', [function(phi) { return f.Value() * Math.cos(k.Value() * phi); }, [0, 0], 0,
 function() { return len.Value() * Math.PI; }], { curveType: 'polar', strokewidth: 2 });
<jsxgraph width="100%" aspect-ratio="1 / 1" title="Rose" description="This construction was copied from JSXGraph examples database: BTW HERE SHOULD BE A GENERATED LINKuseGlobalJS="false">
   /*
   This example is licensed under a 
   Creative Commons Attribution ShareAlike 4.0 International License.
   https://creativecommons.org/licenses/by-sa/4.0/
   
   Please note you have to mention 
   The Center of Mobile Learning with Digital Technology
   in the credits.
   */
   
    var board2 = JXG.JSXGraph.initBoard(BOARDID, { axis: true, boundingbox: [-10, 10, 10, -10], keepaspectratio: true });
    var f = board2.create('slider', [[1, 8], [6, 8], [0, 4, 8]]);
    var len = board2.create('slider', [[1, 7], [6, 7], [0, 2, 8]], { snapWidth: 1, name: 'len' });
    var k = board2.create('slider', [[1, 6], [6, 6], [0, 2, 12]], { snapWidth: 0.2, name: 'k' });
    var c = board2.create('curve', [function(phi) { return f.Value() * Math.cos(k.Value() * phi); }, [0, 0], 0,
    function() { return len.Value() * Math.PI; }], { curveType: 'polar', strokewidth: 2 });
</jsxgraph>
A **rose** or **rhodonea curve** is a sinusoid plotted in polar coordinates. Up to similarity, these curves can all be expressed by a polar equation of the form $$\!\,r=\cos(k\theta).$$ If k is an integer, the curve will be rose shaped with * 2k petals if k is even, and * k petals if k is odd. When k is even, the entire graph of the rose will be traced out exactly once when the value of θ changes from 0 to $2\pi$. When k is odd, this will happen on the interval between 0 and π. (More generally, this will happen on any interval of length $2\pi$ for $k$ even, and $\pi$ for $k$ odd.) The **quadrifolium** is a type of rose curve with n=2. It has polar equation: $$r = \cos(2\theta), \,$$ with corresponding algebraic equation $$(x^2+y^2)^3 = (x^2-y^2)^2.$$
// Define the id of your board in BOARDID

 var board2 = JXG.JSXGraph.initBoard(BOARDID, { axis: true, boundingbox: [-10, 10, 10, -10], keepaspectratio: true });
 var f = board2.create('slider', [[1, 8], [6, 8], [0, 4, 8]]);
 var len = board2.create('slider', [[1, 7], [6, 7], [0, 2, 8]], { snapWidth: 1, name: 'len' });
 var k = board2.create('slider', [[1, 6], [6, 6], [0, 2, 12]], { snapWidth: 0.2, name: 'k' });
 var c = board2.create('curve', [function(phi) { return f.Value() * Math.cos(k.Value() * phi); }, [0, 0], 0,
 function() { return len.Value() * Math.PI; }], { curveType: 'polar', strokewidth: 2 });

license

This example is licensed under a Creative Commons Attribution ShareAlike 4.0 International License.
Please note you have to mention The Center of Mobile Learning with Digital Technology in the credits.